C# - Using Exponent Series and Eulers Number to find EXP Value
I have given here a C# program to find the value of EXP using Exponent Series and without using the library function.
I have used Eulers Number to find out the value of Exponent.
This program will print the values got from the series function MyExp1 and Eulers Number MyExp2 and library function sin.
exp(x) series = 1 + x + x^2 / 2! + x^3 / 3! + x^4 / 4! + x^5 / %! + .....
exp(x) series = power(2.71828, x)
Source Code
using System;
using System.Collections.Generic;
using System.Text;
namespace SoftwareAndFinance
{
class Math
{
const double PI = 3.14159265;
const double EulersNumber = 2.71828;
// exp(x) series = 1 + x + x^2 / 2! + x^3 / 3! + x^4 / 4!
static public double MyExp1(double x)
{
double f = x;
double result = 1 + x;
double fact = 1;
int i = 0;
for (i = 2; i < 20; i++)
{
fact *= i;
f *= x;
result += f / fact;
}
return result;
}
// exp(x) series = power(2.71828, x)
public static double MyExp2(double x)
{
return System.Math.Pow(EulersNumber, x);
}
static void Main(string[] args)
{
for (double i = -2; i <= 3; i += 0.2)
{
Console.WriteLine("{0,8:f2} = {1,8:f4} {2,8:f4} {3,8:f4}", i, System.Math.Exp(i), MyExp1(i), MyExp2(i));
}
}
}
}
Click here to get the C# project along with executable
Output
-2.00 = 0.1353 0.1353 0.1353
-1.80 = 0.1653 0.1653 0.1653
-1.60 = 0.2019 0.2019 0.2019
-1.40 = 0.2466 0.2466 0.2466
-1.20 = 0.3012 0.3012 0.3012
-1.00 = 0.3679 0.3679 0.3679
-0.80 = 0.4493 0.4493 0.4493
-0.60 = 0.5488 0.5488 0.5488
-0.40 = 0.6703 0.6703 0.6703
-0.20 = 0.8187 0.8187 0.8187
0.00 = 1.0000 1.0000 1.0000
0.20 = 1.2214 1.2214 1.2214
0.40 = 1.4918 1.4918 1.4918
0.60 = 1.8221 1.8221 1.8221
0.80 = 2.2255 2.2255 2.2255
1.00 = 2.7183 2.7183 2.7183
1.20 = 3.3201 3.3201 3.3201
1.40 = 4.0552 4.0552 4.0552
1.60 = 4.9530 4.9530 4.9530
1.80 = 6.0496 6.0496 6.0496
2.00 = 7.3891 7.3891 7.3890
2.20 = 9.0250 9.0250 9.0250
2.40 = 11.0232 11.0232 11.0232
2.60 = 13.4637 13.4637 13.4637
2.80 = 16.4446 16.4446 16.4446
Press any key to continue . . .
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