C# - Find Armstrong Number

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An I have given here the program for finding armstrong number of a three digits number.

 

The condition for armstrong number is,

Sum of the cubes of its digits must equal to the number itself.

 

For example, 407 is given as input.

4 * 4 * 4 + 0 * 0 * 0 + 7 * 7 * 7 = 407 is an armstrong number.

 

Source Code

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using System;

using System.Collections.Generic;

using System.Text;

 

namespace Armstrong

{

   class ArmstrongNumber

   {

      static void Main(string[] args)

      {

         System.Console.WriteLine("List of Armstrong Numbers between (100 - 999):");

 

         for(int i = 100; i <= 999; i++)

         {

            int a = i / 100;

            int b = (i - a * 100) / 10;

            int c = (i - a * 100 - b * 10);

 

            int d = a*a*a + b*b*b + c*c*c;

 

            if(i == d)

               System.Console.WriteLine("{0}", i); 

         }

      }

   }

 

}

Output

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List of Armstrong Numbers between (100 - 999):
153
370
371
407

 

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